Exercise 2

2‟s complement of a number is obtained by scanning it from right to left and complementing all the bits after the first appearance of a 1. Thus 2‟s complement of 11100 is 00100. Write a C program to find the 2‟s complement of a binary number.

SOURCE CODE:

/*Program to find 2's complement of a given binary number.*/

#include<stdio.h>

#include<conio.h>

void main()

{

 int a[10],b[10],i,j,n;

 clrscr();

 printf("\nEnter number of bits::\n");

 scanf("%d",&n);

 printf("\nEnter %d bits::\n",n);

 for(i=0;i<n;i++)

  scanf("%d",&a[i]);

 for(i=n-1,j=0;i>=0;i--,j++)

 {

  if(a[i]!=1)

   b[j]=a[i];

  else

  {

   b[j]=a[i];

   i--;

   j++;

   for(;i>=0;i--,j++)

   {

    if(a[i]==1)

     b[j]=0;

    else

     b[j]=1;

   }

  }

 }

 printf("\nTwo's complement of given binary number is::\n");

 for(j=n-1;j>=0;j--)

  printf("%d",b[j]);

}

OUTPUT:

Write a C program to find the roots of a quadratic equation.

SOURCE CODE:

/*Program to find roots of given quadratic equation.*/

#include<stdio.h>

#include<conio.h>

#include<math.h>

void main()

{

 double a,b,c,d,r1,r2,real,imag;

 clrscr();

 printf("\nEnter a,b and c values:\n");

 scanf("%lf%lf%lf",&a,&b,&c);

 d=(b*b)-(4*a*c);

 if(d>0)

 {

  r1=(-b+sqrt(d))/(2*a);

  r2=(-b-sqrt(d))/(2*a);

  printf("\nRoots are:\n r1=%.2lf\tr2=%.2lf",r1,r2);

 }

 else

 if(d==0)

 {

  r1=(-b)/(2*a);

  r2=(-b)/(2*a);

  printf("\nRoots are:\n r1=%.2lf\tr2=%.2lf",r1,r2);

 }

 else

 {

  real=(-b)/(2*a);

  imag=(sqrt(d))/(2*a);

  printf("\nRoots are:\n r1=%.2lf+i%.2lf\tr2=%.2lf-i%.2lf",real,imag,real,imag);

 }

}

OUTPUT:

Write a C program, which takes two integer operands and one operator form the user, performs the operation and then prints the result. (Consider the operators +,-,*, /, % and use Switch Statement)

SOURCE CODE:

/*Program to perform arthmetic operation between two numbers.*/

#include<stdio.h>

#include<conio.h>

void main()

{

 int a,b;

 char op;

 clrscr();

 printf("\nEnter a and b values:\n");

 scanf("%d%d",&a,&b);

 printf("\nEnter operator:\n");

 op=getche();

 switch(op)

 {

  case '+':printf("\na+b=%d",a+b);

  break;

  case '-':printf("\na-b=%d",a-b);

  break;

  case '*':printf("\na*b=%d",a*b);

  break;

  case '/':printf("\na/b=%d",a/b);

  break;

  case '%':printf("\na%%b=%d",a%b);

  break;

  default:printf("\nWrong Arthmetic Operator.");

 }

}

OUTPUT: